swagger-api/swagger-codegen

[SWIFT3] URL parameters are not escaped

Open

#6 400 ouverte le 29 août 2017

Voir sur GitHub
 (11 commentaires) (0 réactions) (0 assignés)HTML (5 474 forks)batch import
Client: SwiftIssue: Bughelp wanted

Métriques du dépôt

Stars
 (12 701 stars)
Métriques de merge PR
 (Aucune PR mergée en 30 j)

Description

Description

swagger-codegen does not properly escape parametrized parts of a URL.

For example:

    var path = "/recipient/{recipient}"
    path = path.replacingOccurrences(of: "{recipient}", with: "\(recipient)", options: .literal, range: nil)

The "recipient" variable should be URLEscaped, but it isn't. Thus, if recipient contains spaces or illegal characters, the request fails. Depending on the source of the parameters, this could also lead to vulnerable code.

Swagger-codegen version

git commit id 18c57a65ed5def618be6495e86fd2d0c73f89882

Swagger declaration file content or url

n/a

Command line used for generation

not relevnt

Steps to reproduce

Use a swagger API that has parameters in the URL, for example: /article/{articleName}, then use "Hello World ../" as articleName

Related issues/PRs

n/a

Suggest a fix/enhancement

Properly url escape the passed parameters:

let param1 = param.addingPercentEncoding(withAllowedCharacters: .urlPathAllowed)

Guide contributeur