Microsoft/TypeScript
Voir sur GitHubNon-exported recursive type alias is inlined until it falls back to any in declarations
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#58 696 ouverte le 29 mai 2024
BugDomain: Declaration EmitHelp Wanted
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- (48 455 stars)
- Métriques de merge PR
- (Merge moyen 6j 17h) (9 PRs mergées en 30 j)
Description
🔎 Search Terms
declarations recursive types
🕗 Version & Regression Information
- This is the behavior in every version I tried (before 4.4 it was either a stack overflow crash or an error on the recursive type)
⏯ Playground Link
💻 Code
// @declaration: true
// @filename: utils.ts
type Recursive<T> = T extends Array<infer V>? Recursive<V>: T;
export const f = <T>(): Recursive<T> => { return null! }
// @filename: index.ts
import { f } from './utils';
export const a = f;
🙁 Actual behavior
In declarations, the type for a is printed as a: () => T extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? V extends (infer V)[] ? any : V : V : V : V : V : V : V : V : V : V : T;
🙂 Expected behavior
Recursive can't be represented without falling back to any (as seen above) so it should just be an error instead of silently to any
Additional information about the issue
Related to #55832