Microsoft/TypeScript

Typescript ESType definition improvements

Open

#27 545 ouverte le 4 oct. 2018

Voir sur GitHub
 (3 commentaires) (0 réactions) (0 assignés)TypeScript (6 726 forks)batch import
Domain: lib.d.tsHelp WantedSuggestion

Métriques du dépôt

Stars
 (48 455 stars)
Métriques de merge PR
 (Merge moyen 2j 7h) (8 PRs mergées en 30 j)

Description

Hi,

The following types can be improved on to be more correct in the lib.es5.d.ts file.

These type improve typically deal with the cases on of the arrays items keys has subset of the other keys, in this case the results is the common subset, with mismatching fields made optional.

This requires functionality in typelevel-ts, however, that is only based on keys. new methods should do and K in keyof T, T[K] extends S[K] ? K : never

// Improved more correctly helper method.
type ObjectOmit<T extends Record<string,any>, O extends Record<string,any>, KeyOfO keyof O> = Pick<T, {
 [K in keyof T] : K extends KeyOfO ? 
                         T[K] extends O[K] | undefined ? never : K // may need a two way extends comparison here.
                          : K
}[keyof T]

export function ObjectAssign<T extends Record<string,any>, U extends Record<string,any>>(target: T, source: U): 
ObjectOverwrite<T, U>
{
  return Object.assign(target, source);
}

export function ArrayConcat<A>(arrayA: A [] , arrayB : A []) : A[]

export function ArrayConcat<B, A extends B>(arrayA: A [], arrayB : B []) : B & Partial<ObjectOmit<A, keyof B>>[]
export function ArrayConcat<A, B extends A>(arrayA: A [], arrayB : B []) : A & Partial<ObjectOmit<B, keyof A>>[]
{
  return arrayA.concat(arrayB) as any
}


export function FilterDefined<T>(items : Array<T> | undefined) : NonNullable<T> []
{
  if (items)
    return items.filter(f => f != undefined) as NonNullable<T> [];
  else
    return []; 
}

Guide contributeur