Python: Find matched line by regular expression for lines of Strings
Nobody has claimed this yet.
Assessment
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Newbie friendliness
- 25/100
- Issue type
- Documentation
- Clarity
- Needs clarification
- Activity status
- Stale
- Tech stack
- python
- Domain
- content, documentation
Research direction
No repository file or documentation location is identified; start by finding where Python tips are maintained and reviewing similar entries. Check the example against values.yaml and the intended regular-expression group lookup. Done means the tip has a clear location, corrected example, and a verifiable explanation of the returned line and match.
Written by the indexing model from the issue text.
Description
import re
##find first match line, and matched group by group number with lines of strings
def find_match_line(r, lines, groupNo=0):
for line in lines:
match = r.search(line)
if match:
return line, match.group(groupNo)
return None, None
###find the "repository:" line in helm file values.yaml, and get the matched repos name
with open("values.yaml", 'r') as file:
lines = file.readlines()
repo_reg = re.compile(r'repository:[ ]' + repos_prefix + "/([a-zA-Z-])")
_,matched_repo_name = find_match_line(repo_reg, lines, 1)
if matched_repos_name:
print("matched repos:%s" % matched_repos_name)
- Dominant language
- Python
- Stars
- 5
- Forks
- 2
- PR merge metrics
- No merged PRs in 30d
Getting set up
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First steps
- Read the whole issue, then the project's contributing guide.
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- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
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