Microsoft/TypeScript

Tail-Recursion Elimination on Conditional Types

Open

#54,082 opened on May 1, 2023

View on GitHub
 (0 comments) (0 reactions) (0 assignees)TypeScript (6,726 forks)batch import
Experience EnhancementHelp WantedSuggestion

Repository metrics

Stars
 (48,455 stars)
PR merge metrics
 (Avg merge 6d 17h) (9 merged PRs in 30d)

Description

Bug Report

🔎 Search Terms

recursion,instantiation,Tail-Recursion

🕗 Version & Regression Information

  • This is the behavior in every version I tried

⏯ Playground Link

Playground link with relevant code

💻 Code

type A = { a: string, b: number }
type B = { a: number, b: string }

type UnionTheTypeOfTheSameKey<R, H> = Omit<R, keyof H> & { [k in keyof H]: k extends keyof R ? R[k] | H[k] : H[k] }

type compute<T> = { [k in keyof T]: T[k] }

type foo<T extends object[], result = {}> = T extends [infer head extends object, ...infer rest extends object[]]
    ? foo<rest, UnionTheTypeOfTheSameKey<result, head>> : result

//  expect ok type test = {a:string|number,b:string|number}
type test = compute<foo<[A, B,]>>

// When the foo length is greater than 33  The result is wrong. type test1 = {a:any,b:any}
type test1 = compute<foo<[A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B]>>

🙁 Actual behavior

// When the foo length is greater than 33 The expected is wrong. type test1 = {a:any,b:any} type test1 = compute<foo<[A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B]>>

🙂 Expected behavior

// When the foo length is Less than 999 expected test1 = {a:string|number,b:string|number} type test1 = compute<foo<[A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B, A, B]>>

Contributor guide